Exam Code: FCP_FCT_AD-7.4
Exam Name: FCP - FortiClient EMS 7.4 Administrator
Version: V13.25
Q & A: 72 Questions and Answers
FCP_FCT_AD-7.4 Free Demo download
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NEW QUESTION: 1
Your network contains an Active Directory domain named contoso.com.
You open Group Policy Management as shown in the exhibit. (Click the Exhibit button.)
You discover that some of the settings configured in the A1 Group Policy object (GPO) fail to apply to the users in the OU1 organizational unit (OU).
You need to ensure that all of the settings in A1 apply to the users in OU1.
What should you do?
A. Enable loopback policy processing in A1.
B. Modify the GPO Status of A1.
C. Modify the policy processing order for OU1.
D. Block inheritance on OU1.
Answer: C
Explanation:
Explanation/Reference:
Explanation:
NEW QUESTION: 2
Given:
import java.io.IOException;
import java.io.file.Path;
import java.io.file.Paths;
public class Path12 {
public static void main(String s[]) throws IOException { Path path = Paths.get("\\sales\\quarter\\..\\qtrlreport.txt");
path.relativize(Paths.get("\\sales\\annualreport.txt"));
if(path.endsWith("annualreport.txt")) {
System.out.println(true);
} else {
System.out.println(false);
}
System.out.println(path);
}
}
What is the result?
A. true \ . . \ . . \annualreport.txt
B. false \sales\quarter\ . . \qtrlreport.txt
C. true . . \ . . \ . . \ annualreport.txt
D. false \quarter\ . . \qtrlreport.txt
Answer: B
Explanation:
The relativize method that can be used to construct a relative path between two
paths.
relativize
Path relativize(Path other)
Constructs a relative path between this path and a given path.
Parameters:
other - the path to relativize against this path
Returns:
the resulting relative path, or an empty path if both paths are equal
Note:
Relativization is the inverse of resolution. This method attempts to construct a relative path that
when resolved against this path, yields a path that locates the same file as the given path. For
example, on UNIX, if this path is "/a/b" and the given path is "/a/b/c/d" then the resulting relative
path would be "c/d". Where this path and the given path do not have a root component, then a
relative path can be constructed. A relative path cannot be constructed if only one of the paths
have a root component. Where both paths have a root component then it is implementation
dependent if a relative path can be constructed. If this path and the given path are equal then an
empty path is returned.
For any two normalized paths p and q, where q does not have a root component,
p.relativize(p.resolve(q)).equals(q)
When symbolic links are supported, then whether the resulting path, when resolved against this
path, yields a path that can be used to locate the same file as other is implementation dependent.
For example, if this path is "/a/b" and the given path is "/a/x" then the resulting relative path may
be "../x". If "b" is a symbolic link then is implementation dependent if "a/b/../x" would locate the
same file as "/a/x".
NEW QUESTION: 3
What is the following description about unsupervised learning?
A. none of the above
B. Unsupervised learning only deals with "features", not "tags"
C. K-means algorithm and SVM algorithm are all unsupervised learning
D. Dimensionality reduction algorithms are not classified as unsupervised learning
Answer: A
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