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NEW QUESTION: 1
By using which process, the financial services provider improved an established sourcing process to convey clear expectations to service providers?
A. DMAIC (define, measure, analyze, improve, control)
B. DMMDV (develop, measure, manage, distribute, maintenance)
C. DMATM (define, manage, analyze, test, maintenance)
D. DMADV (define, measure, analyze, design, verify)
Answer: A

NEW QUESTION: 2
You have a Microsoft 365 subscription. All users use Microsoft Exchange Online.
Microsoft 365 is configured to use the default policy settings without any custom rules.
You manage message hygiene.
Where are suspicious email messages placed by default? To answer, drag the appropriate location to the correct message types. Each location may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.

Answer:
Explanation:

Explanation

NEW QUESTION: 3
Which step is the first for web-based single sign-on login?
A. Authenticate.
B. Present authentication assertion.
C. Request access to protected service.
D. Redirect to IdP to get authenticated.
Answer: C

NEW QUESTION: 4
Ann would like to perform a reliable scan against a remote target. She is not concerned about being stealth at this point.
Which of the following type of scans would be the most accurate and reliable option?
A. A UDP scan
B. A FIN scan
C. A TCP Connect scan
D. A half-scan
Answer: C
Explanation:
A TCP Connect scan, named after the Unix connect() system call is the most accurate scanning method. If a port is open the operating system completes the TCP three-way handshake, and the port scanner immediately closes the connection. Otherwise an error code is returned. Example of a three-way handshake followed by a reset: Source Destination Summary
[192.168.0.8] [192.168.0.10] TCP: D=80 S=49389 SYN SEQ=3362197786 LEN=0 WIN=5840
[192.168.0.10] [192.168.0.8] TCP: D=49389 S=80 SYN ACK=3362197787 SEQ=58695210 LEN=0 WIN=65535
[192.168.0.8]
[192.168.0.10] TCP: D=80 S=49389 ACK=58695211 WIN<<2=5840
[192.168.0.8]
[192.168.0.10] TCP: D=80 S=49389 RST ACK=58695211 WIN<<2=5840