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NEW QUESTION: 1
You need to create an application that processes data on a last-in, first-out (LIFO) basis.
Which data structure should you use?
A. Array
B. Tree
C. Stack
D. Queue
Answer: C
Explanation:
A stack implements LIFO.

NEW QUESTION: 2
あなたの会社の開発者は、テキストメッセージを送信するユーザーをサポートする静的Webアプリを構築しています。アプリは次の要件を満たしている必要があります。
* Webサイトの待ち時間は、地理的に異なる地域のユーザーに対して一貫している必要があります。
*ユーザーはTwitterとFacebookを使用して認証できる必要があります。
*コードには、HTML、ネイティブJavaScript、jQueryのみを含める必要があります。
*コストを最小限に抑える必要があります。
アーキテクチャを完成させるためにどのAzureサービスを使用する必要がありますか？答えるには、適切なサービスを正しい場所にドラッグします。各サービスは、1回使用することも、複数回使用することも、まったく使用しないこともできます。コンテンツを表示するには、分割バーをペイン間でドラッグするか、スクロールする必要がある場合があります。
注：正しい選択はそれぞれ1ポイントの価値があります。

Answer:
Explanation:

NEW QUESTION: 3
Your network contains an Active Directory domain. The domain contains a member server named Server1.
Server1 has a single network connection.
You need to logevery attempt toconnect toServer1 on a restricted port. What should you do?
A. Modify the properties of the inbound firewall rules.
B. Modify the properties of the outbound firewall rules.
C. Change the settings of the private firewall profile.
D. Change the settings of the domain firewall profile.
Answer: A

NEW QUESTION: 4
Which statement about the feasibility condition in EIGRP is true?
A. The EIGRP peer that advertises the prefix to the router is closer to the destination than the router.
B. The EIGRP peer that advertises the prefix cannot be used as a next hop to reach the destination.
C. The EIGRP peer that advertises the prefix to the router has multiple paths to the destination.
D. The prefix is reachable via an EIGRP peer that is in the routing domain of the router.
Answer: A
Explanation:
The advertised metric from an EIGRP neighbor (peer) to the local router is called Advertised Distance (or reported distance) while the metric from the local router to that network is called Feasible Distance. For example, R1 advertises network 10.10.10.0/24 with a metric of 20 to R2. For R2, this is the advertised distance. R2 calculates the feasible distance by adding the metric from the advertised router (R1) to itself. So in this case the feasible distance to network 10.10.10.0/24 is 20 + 50 = 70.

Before a router can be considered a feasible successor, it must pass the feasibility condition rule.
In short, the feasibility condition says that if we learn about a prefix from a neighbor, the advertised
distance from that neighbor to the destination must be lower than our feasible distance to that
same destination.
Therefore we see the Advertised Distance always smaller than the Feasible Distance to satisfy the
feasibility condition.