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NEW QUESTION: 1
Refer to the exhibit.

A WLAN with the SSID "Enterprise" is configured. Which rogue is marked as malicious?
A. a rogue with two clients, broadcasting the SSID "Employee" heard at -50 dBm
B. a rogue with no clients, broadcasting the SSID "Enterprise" heard at -50 dBm
C. a rouge with two clients, broadcasting the SSID "Enterprise" heard at -80 dBm
D. a rogue with two clients, broadcasting the SSID "Enterprise" heard at -50 dBm
Answer: C

NEW QUESTION: 2
Wenn ein Prozess Untergruppen für variable Daten hat und der Prozess über einen langen Zeitraum ausgeführt wird, ist das beste zu verwendende Paar von SPC-Diagrammen eine X-Leiste und _________.
A. R-Diagramm
B. Personendiagramm
C. NP-Diagramm
D. C-Diagramm
Answer: A

NEW QUESTION: 3
Scenario: To access Cisco ASDM, click the PC icon in the Topology window, ASDM and answer the following question as:


The Cisco ASA administration must enable the Cisco ASA to automatically drop suspicious botnet traffic. After the Cisco ASA administrator entered the initial configuration, the Cisco ASA is not automatically dropping the suspicious botnet traffic. What else must be enabled in order to make it work?
A. DNS snooping
B. DNS inspection in the global policy.
C. Periodic download of the dynamic botnet database from Cisco.
D. Botnet traffic filtering on atleast one of the Cisco ASA interface.
E. Manual botnet black and white lists.
Answer: A
Explanation:
Just check all the following settings - certain they will change from time to time

NEW QUESTION: 4
Which one of the following queries selects the customer whose order has the highest total price?
A. CriteriaBuilder cb = ...
Criteria Query <Customer> cq = cb.create Query (Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
B. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.createQuery(Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = sq.from(Order.class);
sq.select (cb.max ( subo.get (Order_ . Total Price) ) ) ;
cq.where(sq.all(o.get(Order_.totalPrice)));
C. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.cteateQuery(Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
D. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.createquery(customer.class)
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
Answer: B
Explanation:
Explanation/Reference:
Incorrect: Not a, not b, not C: use .from not .correlate.
Example:
CriteriaBuilder qb = em.getCriteriaBuilder();
CriteriaQuery<Number> cq = qb.createQuery(Number.class);
Root<Event> root = cq.from(Event.class);
cq.select(qb.max(root.get("dateProcessed")));
cq.where(qb.equal(Event.get("org"), qb.parameter(MyOrgType.class, "myOrg"))); em.createQuery(cq).setParameter("myOrg", myOrg).getSingleResult();
Note:
max(Expression<N> x)
Create an aggregate expression applying the numerical max operation.
Reference: javax.persistence.criteria, Interface CriteriaBuilder