Exam Code: 250-601
Exam Name: Carbon Black Endpoint Detection and Response Technical Specialist
Version: V13.25
Q & A: 72 Questions and Answers
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NEW QUESTION: 1
The industries that are least affected by recessions and economic adversity are referred as which of the following?
A. Interest-sensitive industries
B. Defensive industries
C. Cyclical industries
D. Growth industries
Answer: B
NEW QUESTION: 2
The project team needs to get additional data available in the market to clarify the specifications of the product in scope. What type of bid document should be used in this situation?
A. Request for quote (RFQ)
B. Request for information (RFI)
C. Request for proposal (RFP)
D. Request for solution (RFS)
Answer: B
NEW QUESTION: 3
Your database instance has the following parameter setting:
OS_AUTHENT_PREFIX = OPS$
You execute the following command:
And then grant OPS$GUEST_USER the CREATE SESSION privilege.
Which two statements are true? (Choose two.)
A. GUEST_USER is forced to change the password at the first login.
B. The authentication details for GUEST_USER are stored in the database password file.
C. GUEST_USER can log on to the database without specifying a username and password.
D. GUEST_USER can query the tables created in the USERS tablespace by default.
E. A local GUEST_USER OS account should exist before GUEST_USER can log on to the database.
Answer: C,E
NEW QUESTION: 4
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:
You need to determine the total number of customers who have either deposit accounts or loan accounts, but not both types of accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
C. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct L WHERE D.CustNo = L.CustNo
D. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
E. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
Answer: B
Explanation:
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx
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