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NEW QUESTION: 1
How should items in the Product Backlog be ordered?
A. Grouped by business features first and then chronologically by date of original business request.
B. Prioritized across all business units and features first and then by list order in the Product Backlog.
C. Chronologically by date of original business request first and then by list order in the Product Backlog
D. Alphabetically by the business unit first and then by list order in the Product Backlog
Answer: B

NEW QUESTION: 2

*Item_ID, Integer: PK
*Item_name, Varchar (20)
*Price, Numeric (10, 2)
*Quan, Integer

public static void updatePrices{ // #1: missing line
Connection con) throws SQLException {
// #2: missing line
PreparedStatement updatePrices = con.prepareStatement (updatePricesString);
// #3: missing line { // #4: missing line updatePrices.executeUpdate(); } }

A. 1. HashMap<Integer> newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? Where item_id '?' ";
3.For (Integer x: newPrice)
4.updatePrice.setInt(1, x);
B. 1. HashMap<Integer, Float> newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? Where item_id '?' ";
3.For (map.Entry<Integer, String> x : newPrices.entrySet())
4.UpdatePrices.setInt(1, x.getvalue().floatValue()); updatePrice.setString (2, x.getvalue().floatValue()
C. 1. HashMap<Integer, String> newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? WHERE item_name '?' ";
3.For (map.Entry<Integer, String> x : newPrices.entrySet())
4.UpdatePrices.setFloat(1, x.getvalue().floatValue()); updatePrice.setString (2, x.getKey());
D. 1. HashMap<Integer, String> newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? Where item_id '?' ";
3.For (map.Entry<Integer, String> x : newPrices.entrySet())
4.UpdatePrices,setString(1, x.getKey()); updatePrices.setFloat(2, x.getValue().floatValue());
E. 1. HashMap<Integer, Float> newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? WHERE item_id '?' ";
3.For (map.Entry<Integer, String> x : newPrices.entrySet())
4.UpdatePrices.setFloat(1, x.getvalue().floatValue()); updatePrice.setString (2,
x.getKey().intValue());
F. 1. HashMap<Integer, Float> newPrices,
2.StringupdatePriceString = "UPDATE inventory SET price =? Where item_id '?' ";
3.For (map.Entry<Integer, String> x : newPrices.entrySet())
4.UpdatePrices.setInt(1, x.getvalue().floatValue()); updatePrice.setString (2, x.getvalue());
Answer: B
Explanation:
The first line should be HashMap<Integer, Float> newPrices,
as in SQL numeric represent a float number, not an integer or string.
We also make sure to use floatValue() both in appropriate places in line 4.
Note: Map is an object that maps keys to values. A map cannot contain duplicate keys: Each key
can map to at most one value. It models the mathematical function abstraction.

NEW QUESTION: 3
An organization has created 5 IAM users. The organization wants to give them the same login ID but different passwords. How can the organization achieve this?
A. The organization should create various groups and add each user with the same login ID to different groups. The user can login with their own group ID
B. The organization should create each user in a separate region so that they have their own URL to login
C. It is not possible to have the same login ID for multiple IAM users of the same account
D. The organization should create a separate login ID but give the IAM users the same alias so that each one can login with their alias
Answer: C
Explanation:
Explanation
AWS Identity and Access Management is a web service which allows organizations to manage users and user permissions for various AWS services.
Whenever the organization is creating an IAM user, there should be a unique ID for each user. It is not possible to have the same login ID for multiple users. The names of users, groups, roles, instance profiles must be alphanumeric, including the following common characters: plus (+), equal (=), comma (,), period (.), at (@), and dash (-).
http://docs.aws.amazon.com/IAM/latest/UserGuide/Using_SettingUpUser.html