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NEW QUESTION: 1
Refer to the exhibit. What is the effect of the given command sequence?
crypto ikev1 policy 1
encryption aes
hash md5
authentication pre-share
group 2
lifetime 14400
A. It configures IKE Phase 1
B. It configures IPSec Phase 2
C. It configures a site-to-stie VPN Tunnel
D. It configures a crypto policy with a key size of 14400
Answer: A

NEW QUESTION: 2
When configuring EIGRP to run across a 56 Kbps serial PPP link, what command do you need to put under the serial interface ensure proper convergence of EIGRP routes?
A. bandwidth 56
B. ip bandwidth-percent eigrp 1 56
C. ip bandwidth-percent eigrp 1 56000
D. bandwidth 56000
Answer: A
Explanation:
Explanation/Reference:
Explanation:
When configuring serial links using EIGRP it is important to configure the bandwidth setting on the interface. If the bandwidth setting is not changed for these interfaces EIGRP assumes the default bandwidth on the link instead of the true bandwidth. If the link is slower, the router may not be able to converge, routing updates might become lost, or suboptimal path selection may result. Router(config-if)
#bandwidth kilobits The value, kilobits, indicates the intended bandwidth in kilobits per second. For generic serial interfaces, such as PPP or HDLC, set the bandwidth to the line speed.

NEW QUESTION: 3
What development tool is available for creating SAP HANA XSA and HDI information models?
Please choose the correct answer.
Response:
A. Database Explorer
B. SAP HANA Studio
C. SAP Web IDE for SAP HANA
D. SAP HANA Web-Based Development Workbench
Answer: C

NEW QUESTION: 4
View the Exhibit and examine the description for the CUSTOMERS table.

You want to update the CUST_INCOME_LEVEL and CUST_CREDIT_LIMIT columns for the customer with the CUST_ID 2360. You want the value for the CUST_INCOME_LEVEL to have the same value as that of the customer with the CUST_ID 2560 and the CUST_CREDIT_LIMIT to have the same value as that of the customer with CUST_ID 2566.
Which UPDATE statement will accomplish the task?
A. UPDATE customers
SET (cust_income_level, cust_credit_limit) = (SELECT
cust_income_level, cust_credit_limit
FROM customers
WHERE cust_id=2560 AND cust_id=2566)
WHERE cust_id=2360;
B. UPDATE customers
SET (cust_income_level, cust_credit_limit) = (SELECT
cust_income_level, cust_credit_limit
FROM customers
WHERE cust_id IN(2560, 2566)
WHERE cust_id=2360;
C. UPDATE customers
SET cust_income_level = (SELECT cust_income_level
FROM customers
WHERE cust_id = 2560),
cust_credit_limit = (SELECT cust_credit_limit
FROM customers
WHERE cust_id = 2566)
WHERE cust_id=2360;
D. UPDATE customers
SET (cust_income_level, cust_credit_limit) = (SELECT
cust_income_level, cust_credit_limit
FROM customers
WHERE cust_id=2560 OR cust_id=2566)
WHERE cust_id=2360;
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Updating Two Columns with a Subquery
You can update multiple columns in the SET clause of an UPDATE statement by writing multiple subqueries. The syntax is as follows:
UPDATE table
SET column
(SELECT column
FROM table
WHERE condition)
[,
column
(SELECT column
FROM table
WHERE condition)]
[WHERE condition ] ;