Exam Code: A00-215
Exam Name: SAS Certified Associate: Programming Fundamentals Using SAS 9.4
Version: V13.25
Q & A: 72 Questions and Answers
A00-215 Free Demo download
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NEW QUESTION: 1
Which of the following is a benefit of ASM fast disk resync?
A. The failed disk is automatically reformatted and then resynchronized to speed up the recovery process.
B. Hot spare disks are automatically configured and added to the disk group.
C. By default, the failed disk is not dropped from the disk group ever, protecting you from loss of that disk.
D. Disk data is never lost.
E. Failed disks are taken offline immediately but are not dropped.
Answer: E
Explanation:
Explanation/Reference:
Explanation:
ASM Fast Mirror Resync
NEW QUESTION: 2
Which three statements about FabricPath are true? (Choose three.)
A. A vPC+ peer link can be formed out of F2 ports only.
B. F1 ports must be placed into a separate VDCs.
C. Only FabricPath VLANs can cross a FabricPath domain.
D. A vPC+ peer link can be formed out of F1 or F2 ports only.
E. With FabricPath, vPC must be changed to vPC+.
Answer: C,D,E
Explanation:
After you enable FabricPath on the switches that you are using, you can configure an Ethernet interface or a port-channel interface as a FabricPath interface. If one member of the port channel is in FabricPath mode, all the other members will be in FabricPath mode. After you configure the interface as a FabricPath interface, it automatically becomes a trunk port, capable of carrying traffic for multiple VLANs. You can also configure all the ports on the switch as FabricPath interfaces simultaneously. The following interface modes carry traffic for the following types of VLANs:
Interfaces on the switch that are configured as FabricPath interfaces can carry traffic only for
FabricPath VLANs.
Interfaces on the switch that are not configured as FabricPath interfaces carry traffic for the
following:
-
FabricPath VLANs -
Classical Ethernet (CE) VLANShttp://www.cisco.com/c/en/us/td/docs/switches/datacenter/nexus5000/sw/fabricpath/513_n1_1/N5 K_FabricPath_Configuration_Guide/fp_n5k_interfaces.html
NEW QUESTION: 3
Which of the following answers is described as a random value used in cryptographic algorithms to ensure that patterns are not created during the encryption process?
A. OTP - One Time Pad
B. IV - Initialization Vector
C. Ciphertext
D. Stream Cipher
Answer: B
Explanation:
Explanation/Reference:
The basic power in cryptography is randomness. This uncertainty is why encrypted data is unusable to someone without the key to decrypt.
Initialization Vectors are a used with encryption keys to add an extra layer of randomness to encrypted data. If no IV is used the attacker can possibly break the keyspace because of patterns resulting in the encryption process. Implementation such as DES in Code Book Mode (CBC) would allow frequency analysis attack to take place.
In cryptography, an initialization vector (IV) or starting variable (SV)is a fixed-size input to a cryptographic primitive that is typically required to be random or pseudorandom. Randomization is crucial for encryption schemes to achieve semantic security, a property whereby repeated usage of the scheme under the same key does not allow an attacker to infer relationships between segments of the encrypted message. For block ciphers, the use of an IV is described by so-called modes of operation. Randomization is also required for other primitives, such as universal hash functions and message authentication codes based thereon.
It is define by TechTarget as:
An initialization vector (IV) is an arbitrary number that can be used along with a secret key for data encryption. This number, also called a nonce, is employed only one time in any session.
The use of an IV prevents repetition in data encryption, making it more difficult for a hacker using a dictionary attack to find patterns and break a cipher. For example, a sequence might appear twice or more within the body of a message. If there are repeated sequences in encrypted data, an attacker could assume that the corresponding sequences in the message were also identical. The IV prevents the appearance of corresponding duplicate character sequences in the ciphertext.
The following answers are incorrect:
- Stream Cipher: This isn't correct. A stream cipher is a symmetric key cipher where plaintext digits are combined with pseudorandom key stream to product cipher text.
- OTP - One Time Pad: This isn't correct but OTP is made up of random values used as key material.
(Encryption key) It is considered by most to be unbreakable but must be changed with a new key after it is used which makes it impractical for common use.
- Ciphertext: Sorry, incorrect answer. Ciphertext is basically text that has been encrypted with key material (Encryption key)
The following reference(s) was used to create this question:
For more details on this TOPIC and other Qs of the Security+ CBK, subscribe to our Holistic Computer Based Tutorial (CBT) at http://www.cccure.tv
and
whatis.techtarget.com/definition/initialization-vector-IV
and
en.wikipedia.org/wiki/Initialization_vector
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