Exam Code: C-THR83-2411
Exam Name: SAP Certified Associate - Implementation Consultant - SAP SuccessFactors Recruiting: Recruiter Experience
Version: V13.25
Q & A: 72 Questions and Answers
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NEW QUESTION: 1
Refer to the exhibit.
Which action is taken to ensure that the relay agent forwards the DHCP BOOTREQUEST packet to a DHCP server?
A. Configure the IP address of the DHCP server.
B. Enable the DHCP relay agent.
C. Configure the interface of the DHCP server as untrusted.
D. Verify the DHCP snooping bindings.
Answer: B
NEW QUESTION: 2
공개 서브넷에서 NAT (Network Address Translation) 장치로 사용할 인스턴스를 시작한 후에 NAT 장치가 사설 서브넷의 인터넷 바운드 트래픽 대상이 되도록 경로 테이블을 수정합니다. 개인 서브넷의 인스턴스에서 인터넷으로 아웃 바운드 연결을 시도하면 성공하지 못합니다.
다음 중 문제를 해결할 수있는 단계는 무엇입니까?
A. 개인 서브넷의 인스턴스에 탄성 IP 주소 연결
B. NAT 인스턴스에 두 번째 ENI (Elastic Network Interface) 연결 및 사설 서브넷에 배치
C. 개인 서브넷의 인스턴스에 두 번째 ENI (Elastic Network Interface) 연결하고 공용 서브넷에 배치합니다.
D. NAT 인스턴스에서 원본 / 대상 검사 특성 사용 안 함
Answer: D
NEW QUESTION: 3
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, COUNT(OrderAmount) AS OrderAmount FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID ORDER BY OrderAmount DESC
B. ShippingCountry) cs WHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(OrderAmount) DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID Where o.Rnk = 1
D. SELECT CustomerID, CustomerName, ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK() OVER (PARTITION BY c.CustomerID ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk FROM Customer c INNER JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c.CustomerName,
E. ShippingCountry) cs WHERE Rnk = 1
F. SELECT CustomerID, CustomerName, ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName,
G. ShippingCountry, RANK() OVER (PARTITION BY c. CustomerID ORDER BY o. OrderAmount DESC) AS Rnk FROM Customer c INNER JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c.CustomerName,
Answer: A
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