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NEW QUESTION: 1
When connected to the Check Point R80 Management Server using the SmartConsole the first administrator to connect has a lock on:
A. The entire Management Database and all sessions and other administrators can connect only as Read-only.
B. The entire Management Database and other administrators can connect to make changes only if the first administrator switches to Read-only.
C. Only the objects being modified in the Management Database and other administrators can connect to make changes using a special session as long as they all connect from the same LAN network.
D. Only the objects being modified in his session of the Management Database and other administrators can connect to make changes using different sessions.
Answer: D

NEW QUESTION: 2
Lightningナレッジを実装するときにどの構成アイテムを作成する必要がありますか？
A. 商品タイプ
B. ファイルの種類
C. 添付ファイルの種類
D. レコードタイプ
Answer: D

NEW QUESTION: 3
Which accounting attribute group will capture a customer's accounting invoice and the cash applied to that invoice?
A. System Transaction identifiers
B. Distribution identifiers
C. Tax attribute
D. Business Flow
Answer: A
Explanation:
System transaction identifiers provide a link between an accounting event and its associated transaction or document. An identifier is the primary key of the underlying subledger transaction, usually the name of the surrogate key column on the transaction (header) associated with the accounting event. At least one system transaction identifier must be defined for the accounting event class.
When an accounting event is captured, system transaction identifiers, along with other required event data, are validated for completeness. Use event entities to tie subledger transaction entities with their accounting representation. The Financial Services Accounting Hub uses event entities to maintain the system transaction identifiers that uniquely identify the subledger transactions associated with the accounting events.

NEW QUESTION: 4
The SAS data set PETS is sorted by the variables TYPE and BREED.
The following SAS program is submitted:
proc print data = pets;
var type breed;
sum number;
run;
What is the result?
A. The SUM statement produces both a grand total of NUMBER and subtotals of NUMBER for each value of TYPE.
B. Nothing is produced by the SUM statement; the program fails to execute.
C. The SUM statement produces only a grand total of NUMBER.
D. The SUM statement produces only subtotals of NUMBER for each value of TYPE.
Answer: C