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H20-699_V2.0 real exams

Exam Code: H20-699_V2.0

Exam Name: HCSE-Field-Smart PV(Utility) V2.0

Version: V13.25

Q & A: 72 Questions and Answers

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NEW QUESTION: 1
You are asked to use Performance Modeler to Transfer a cube. The target cube already exists in the target system but the source cube contains an additional dimension.
What happens to the target cube and its data?
A. The additional dimension is added and the existing data is placed in the first leaf of the new dimension.
B. The additional dimension is added and the existing data is propagated across all leaves of the new dimension.
C. The additional dimension is not added and the existing data remains in place.
D. The additional dimension is added and the existing data is deleted.
Answer: A

NEW QUESTION: 2
Wenn wir sagen, dass eine Reihe von Tests eine 100% ige strukturelle Entscheidungsabdeckung für ein bestimmtes Modul in einem Programm erreicht hat, was bedeutet das?
1 Kredit [K2]
Anzahl der richtigen Antworten: 1
A. Dass alle in diesem Modul vorhandenen Fehler bei diesen Tests unbedingt aufgedeckt wurden.
B. Jeder Datenfluss in diesem Modul wurde von diesen Tests mindestens einmal ausgeführt.
C. Dass jeder Pfad durch dieses Modul von diesen Tests mindestens einmal ausgeführt wurde.
D. Dass jeder Kontrollflusszweig durch diese Tests mindestens einmal ausgeführt wurde.
Answer: D

NEW QUESTION: 3
Which statement about using the pause and annotate mode is true?
A. Anyone with Share pod permissions can mark up the snapshot with Whiteboard tools.
B. Anyone with Chat pod permissions can mark up the snapshot with Whiteboard tools.
C. Anyone with File Share pod permissions can mark up the snapshot with Whiteboard tools.
D. Anyone with Camera and Voice pod permissions can mark up the snapshot with Whiteboard tools.
Answer: A

NEW QUESTION: 4
Assuming that the code below has been executed successfully, which of the following expressions will always evaluate to True? (Select two answers) import random v1 = random. random() v2 = random. random()
A. random.choice{[1,2,3]) > 0
B. v1 < 1
C. v1 == v2
D. len(random. sample([1,2,3],1)) > 2
Answer: A,B

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