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NEW QUESTION: 1
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, die dasselbe Szenario darstellen. Jede Frage in der Reihe enthält eine eindeutige Lösung, mit der die angegebenen Ziele erreicht werden können. Einige Fragensätze haben möglicherweise mehr als eine richtige Lösung, während andere möglicherweise keine richtige Lösung haben.
Nachdem Sie eine Frage in diesem Abschnitt beantwortet haben. Sie werden NICHT in der Lage sein, dorthin zurückzukehren. Infolgedessen werden diese Fragen nicht im Überprüfungsbildschirm angezeigt.
Sie haben eine Datenbank, die Bestellungen und Lieferungen für Kunden in Nordamerika verfolgt. Die Datenbank enthält die folgenden Tabellen:
Vertrieb.Kunden

Anwendung.Städte

Sales.CustomerCategories

Ihr Unternehmen entwickelt eine neue soziale Anwendung, die Kunden anhand der Entfernung zwischen ihren Lieferorten miteinander verbindet.
Sie müssen eine Abfrage schreiben, die den nächsten Kunden zurückgibt.
Lösung: Sie führen die folgende Transact-SQL-Anweisung aus:
SELECT TOP 1 B.CustomerID, A.DeliveryLocation.STDistance (B.DeliveryLocation) AS Dist FROM Sales.Customers ALS CROSS JOIN Sales.Customers AS B WHERE A.CustomerID = @custID UND A.CustomerID <> B.CustomerID ORDER BY Dist Die Variable @custID ist auf einen gültigen Kunden eingestellt.
Entspricht die Lösung dem Ziel?
A. Nein
B. Ja
Answer: A

NEW QUESTION: 2
CORRECT TEXT
Problem Scenario 90 : You have been given below two files
course.txt
id,course
1 ,Hadoop
2 ,Spark
3 ,HBase
fee.txt
id,fee
2,3900
3,4200
4,2900
Accomplish the following activities.
1. Select all the courses and their fees , whether fee is listed or not.
2. Select all the available fees and respective course. If course does not exists still list the fee
3. Select all the courses and their fees , whether fee is listed or not. However, ignore records having fee as null.
Answer:
Explanation:
See the explanation for Step by Step Solution and configuration.
Explanation:
Solution :
Step 1:
hdfs dfs -mkdir sparksql4
hdfs dfs -put course.txt sparksql4/
hdfs dfs -put fee.txt sparksql4/
Step 2 : Now in spark shell
// load the data into a new RDD
val course = sc.textFile("sparksql4/course.txt")
val fee = sc.textFile("sparksql4/fee.txt")
// Return the first element in this RDD
course.fi rst()
fee.fi rst()
//define the schema using a case class case class Course(id: Integer, name: String) case class Fee(id: Integer, fee: Integer)
// create an RDD of Product objects
val courseRDD = course.map(_.split(",")).map(c => Course(c(0).tolnt,c(1))) val feeRDD =fee.map(_.split(",")).map(c => Fee(c(0}.tolnt,c(1}.tolnt)) courseRDD.first() courseRDD.count(}
feeRDD.first()
feeRDD.countQ
// change RDD of Product objects to a DataFrame val courseDF = courseRDD.toDF(} val feeDF = feeRDD.toDF{)
// register the DataFrame as a temp table courseDF. registerTempTable("course") feeDF.
registerTempTablef'fee")
// Select data from table
val results = sqlContext.sql(......SELECT' FROM course """ )
results. showQ
val results = sqlContext.sql(......SELECT' FROM fee......)
results. showQ
val results = sqlContext.sql(......SELECT * FROM course LEFT JOIN fee ON course.id = fee.id......) results-showQ val results ="sqlContext.sql(......SELECT * FROM course RIGHT JOIN fee ON course.id = fee.id "MM ) results. showQ val results = sqlContext.sql(......SELECT' FROM course LEFT JOIN fee ON course.id = fee.id where fee.id IS NULL" results. show()

NEW QUESTION: 3
継続的なレプリケーションを実行するための主要な目的は何ですか？
A. RPOをほぼゼロに減らします。
B. データのアーカイブを実行しないでください。
C. 重複排除率を下げます。
D. データのバックアップを実行しないでください。
Answer: D

NEW QUESTION: 4
Refer to the exhibit. The access list has been configured on the Gi0/0/0/0 interface in the inbound direction.
Which four packets that are sourced from 10.1.1.1 TCP port 1060, if they are routed to the Gi0/0/0/0 interface, will be permitted? (Choose four)

A. destination IP address: 192.168.15.49, destination TCP port: 80
B. destination IP address: 192.168.15.49, destination TCP port: 8080
C. destination IP address: 192.168.15.41, destination TCP port: 8080
D. destination IP address: 192.168.15.46, destination TCP port: 80
E. destination IP address: 192.168.15.36, destination TCP port: 80
F. destination IP address: 192.168.15.37, destination TCP port: 8080
Answer: A,B,D,E