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NEW QUESTION: 1
Welche der folgenden physischen Sicherheitskontrollen ist für ein falsches Positiv am anfälligsten?
A. Ausweis
B. Videokamera
C. Biometrisches Gerät
D. Näherungsleser
Answer: D

NEW QUESTION: 2
Which two statements regarding a Machine Catalog are valid? (Choose two.)
A. A Machine Catalog can be rolled back to a previous master image.
B. A single Machine Catalog can contain both Server and Desktop OS machines.
C. A Machine Catalog created with Machine Creation Services (MCS) can have multiple master images.
D. A Machine Catalog can span XenApp/XenDesktop Sites.
E. A Machine Catalog can span hypervisor hosts.
Answer: A,C

NEW QUESTION: 3
During a blackbox pen test you attempt to pass IRC traffic over port 80/TCP from a compromised web enabled host. The traffic gets blocked; however, outbound HTTP traffic is unimpeded.
What type of firewall is inspecting outbound traffic?
A. Packet Filtering
B. Application
C. Stateful
D. Circuit
Answer: B
Explanation:
An application firewall is an enhanced firewall that limits access by applications to the operating system (OS) of a computer. Conventional firewalls merely control the flow of data to and from the central processing unit (CPU), examining each packet and determining whether or not to forward it toward a particular destination. An application firewall offers additional protection by controlling the execution of files or the handling of data by specific applications.
References: http://searchsoftwarequality.techtarget.com/definition/application-firewall

NEW QUESTION: 4



A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk FROM Customer c INNER JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY OrderAmount DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID WHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, COUNT(OrderAmount) DESC) AS OrderAmount FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID ORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(OrderAmount) DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID WHERE o.Rnk = 1
Answer: D