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250-587 real exams

Exam Code: 250-587

Exam Name: Symantec Data Loss Prevention 16.x Administration Technical Specialist

Version: V13.25

Q & A: 72 Questions and Answers

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NEW QUESTION: 1
主に次の理由により、他の侵入防止および検出テクノロジーに加えて、Webアプリケーションファイアウォールが必要です。
A. Webサービスは攻撃を受けやすいです。
B. Webサービスには独自の法医学的証拠が必要
C. アプリケーションのソースコードの変更を防ぎます
D. Webアプリケーションプロトコルを認識します。
Answer: A

NEW QUESTION: 2
ラボシミュレーション-EBGPおよびIBGP
シナリオ
RADO Network Ltd会社のネットワークエンジニアとして働いています。同僚は、顧客ネットワークをシミュレートするPOCラボをセットアップして、2つの異なる自律システム間でルートが交換されるときのBGPプロトコルの動作について調査しました。
トポロジを確認します。 R1ルーターでIBGPおよびEBGPの問題を特定して修正する必要があります。
トポロジの詳細
AS64520
R1、R2、およびR3はAS 64520上の3つのルーターであり、OSPFはIGPルーティングプロトコルです。
*それらの間で構成されます。
IBGPは、ピアグループを使用してR1、R2、およびR3ルーター間で構成されます。
* Loopback0アドレスはIBGPピアリングに使用されます。 R1、R2、およびに設定されたLoopback0アドレス
* R3はAS64525のBGPドメインにアドバタイズされます。
AS64525
RAとRBはAS 64525上の2つのルーターであり、EIGRPはIGPルーティングプロトコルです。
*それらの間で構成されます。
Loopback0アドレスは、IBGPピアリングに使用されます。 Loopback0アドレスはRAおよびRBで設定されます
*およびAS64525のBGPドメインにアドバタイズされます。
R1とRAは、物理インターフェイスアドレスを使用してEBGPネイバー関係を形成します。
* R2とRBは、物理インターフェイスアドレスを使用してEBGPネイバー関係を形成します。
*シミュレーション要件
R1とRAルーター間のEBGP近隣関係の問題を特定して修正します。
* R1とR2、およびR1とR3間のIBGPネイバー関係の問題を特定して修正します。
*構成の誤りや構成の誤りを削除して、問題を修正することのみが許可されます。
*問題に影響を与えないその他の初期設定は変更しないでください。
R1ルーターで2つの問題を修正した後、最終的なBGPテーブルが次のように表示されます。
*特記事項:ポイントの最大数を取得するには、ルーターR1でIBGPおよびEBGPネイバーの問題を修正する必要があります。
アドレスファミリを使用せずにBGPを設定する必要があります。 BGPピアグループ名は変更しないでください。
コンソールのログ機能とデバッグ機能は無効になっています。
* showコマンドを使用して、BGPネイバー関係を確認します。


Answer:
Explanation:
For EBGP and IBGP labs you have to make corrections to the configuration in a router R1.
You have only access to Router R1. R1 and RA should be neighbors through EBGP.
On R1 you will find this command:
(config-router)#Neighbor 209.165.277.2 remote-as 64525
The ip address here is wrong , delete this command using:
(config-router)#No Neighbor 209.165.277.2 remote-as 64525
And replace it with new command with the correct IP of RA E0/1 interface by typing this command:
(config-router)#Neighbor 209.165.201.2 remote-as 64525
R1 and R2 and R3 are neighbors through IBGP, and R1 use the peer-group IBGP to form neighborship between R1 and R2, and between R1 and R3, but actually there is an issue with the IBGP peer-group commands in R1 You will find in R1 these following commands:
(config-router)#neighbor IBGP peer-group
(config-router)#neighbor IBGP remote-as 64550
(config-router)#neighbor IBGP next-hop-self
(config-router)#neighbor IBGP update-source loopback 0
You must correct the Remote-AS for the Peer-Group IBGP to 64520 to form the neighborship correctly. Be aware, if you delete the config with no neighbor IBGP remote-as 64550 you also will delete the following lines:
(config-router)#neighbor IBGP peer-group
(config-router)#neighbor IBGP next-hop-self
(config-router)#neighbor IBGP update-source loopback 0
So don't delete the line regarding the remote-as, just replace it with:
(config-router)#neighbor IBGP remote-as 64520
In the Scenario regarding the Lab, they tell you how the routing-table should look if you have done everything right! So if you routing-table on R1 looks like the one they posted in the scenario you have done everything right and can go on to the next topic. You have to use the command
"#show ip bgp " to show bgp routing table , dont use "#show ip route"
Note:
+ In the second statement we fix the IBGP group to "remote-as 64520" without removing the wrongly configured IBGP group ("neighbor IBGP remote-as 64550") because if we remove this statement, other related statements of IBGP (three statements "neighbor IBGP update-source Loopback0", "neighbor 172.16.2.2 peer-group IBGP", "neighbor 172.16.3.3 peer-group IBGP") will be removed automatically because IBGP group no longer exists.
+ Also in statement 2 the "IBGP" group must be written in capital. You will receive an error if writing it in lowercase.
+ The IP addresses in the exam are different but the concept is still the same so please read the question carefully.
After solving the problem don't forget to verify with the "show ip bgp" command. You must see all the Loopback interfaces of other routers. Otherwise please check your commands again.

NEW QUESTION: 3
When creating a function, in which section will you typically find the RETURN keyword?
A. DECLARATIVE
B. EXECUTABLE and HEADER
C. HEADER only
D. DECLARATIVE,EXECUTABLE and EXCEPTION HANDLING
Answer: B
Explanation:
The header of the function contains the RETURN keyword and identifies the data type that needs to be returned to the calling block. The RETURN statement in the executable section of the function performs the actual returning of the value. The header section defines the return data type of the value and the executable section does the actual returning.
Incorrect Answers:
A: You need a RETURN Statement in the EXECUTABLE section as well.B. You will not find a RETURN in the declaration section.
D: You will not find a RETURN statement in either section..

NEW QUESTION: 4
You have a server named Server1 that runs Windows Server 2016 and is configured as a domain controller.
You install the DNS Server server role on Server1.
You plan to store a DNS zone in a custom Active Directory partition.
You need to create a new Active Directory partition for the zone.
What should you use?
A. Ntdsutil.exe
B. New-ADObject
C. DNS Manager
D. Active Directory Sites and Services
E. Set-DnsServer
Answer: C
Explanation:
References:
https://www.businessnewsdaily.com/11019-set-up-configure-dns-on-windows-server-2016.html

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