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NEW QUESTION: 1
If a government adopted an expansionary fiscal policy of cutting direct taxes, the businesses that would benefit most would be those whose products:
A. Are largely exported
B. Are largely bought on credit
C. Have a high price elasticity of demand
D. Are sold mainly to individual consumers
Answer: D

NEW QUESTION: 2
Can the option "Windows Shell Shortcut creation: Do Nothing" be used in combination with the RES Workspace Manager Shell?
A. Yes, and the session will not be managed.
B. Yes, and applications will not be managed.
C. No, RES Workspace Manager will not continue when the session is started
D. No, RES Workspace Manager will automatically revert to 'Replace'.
Answer: D

NEW QUESTION: 3
You are working for a company that designs mobile applications. They maintain a server where player records are assigned to their different games. The tracking system is new and in development.
The application uses Entity Framework to connect to an Azure Database. The database holds a Player table and Game table.
When adding a player, the code should insert a new player record, and add a relationship between an existing game record and the new player record.
The application will call CreatePlayerWithGame with the correct gameIdand the playerId to start the process.
(Line numbers are included for reference only.)

For each of the following statements, select Yes if the statement is true. Otherwise, select No.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

Many-to-many relationships without an entity class to represent the join table are not yet supported. However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Post)
WithMany(p => p.PostTags)
HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Tag)
WithMany(t => t.PostTags)
HasForeignKey(pt => pt.TagId);
}
}