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NEW QUESTION: 1
Account combinations can be created and/or modified using the Import Account Combinations file-based data import (FBDI).
Which represents the appropriate upload steps?
A. Submit the Import Account Combinations process, then insert rows into the GL_MULTI_COMBINATIONS_INT table using the FBDI template.
B. Insert rows into the GL_BULK_COMBINATIONS_INT table using the FBDI template and then submit the Import Account Combinations process.
C. Insert rows into the GL_MULTI_COMBINATIONS_INT table using the FBDI template and then submit the Import Account Combinations process.
D. Submit the Import Account Combinations process, then insert rows into the GL_BULK_COMBINATIONS_INT table using the FBDI template.
Answer: B

NEW QUESTION: 2
Universal Container wants to display a message when a case needs follow up. What can be used to display different text on the case record depending on the number of days a case is opened?
A. Formula Field
B. Lightning Process Builder
C. Case Process
D. Workflow Update
Answer: A

NEW QUESTION: 3
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.0.255.255.255.254
B. Permit 10.0.0.1.0.0.0.254
C. Permit 10.0.0.0.0.0.0.1
D. Permit 10.0.0.1.0.0.0.0
Answer: B
Explanation:
Explanation
Remember, for the wildcard mask, 1s are I DON'T CARE, and 0s are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).

The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 000 ) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.